ln(4x+1)=ln(x^2)+4

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Solution for ln(4x+1)=ln(x^2)+4 equation: 


Simplifying
ln(4x + 1) = ln(x2) + 4

Reorder the terms:
ln(1 + 4x) = ln(x2) + 4
(1 * ln + 4x * ln) = ln(x2) + 4
(1ln + 4lnx) = ln(x2) + 4

Multiply ln * x2
1ln + 4lnx = lnx2 + 4

Reorder the terms:
1ln + 4lnx = 4 + lnx2

Solving
1ln + 4lnx = 4 + lnx2

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1lnx2' to each side of the equation.
1ln + 4lnx + -1lnx2 = 4 + lnx2 + -1lnx2

Combine like terms: lnx2 + -1lnx2 = 0
1ln + 4lnx + -1lnx2 = 4 + 0
1ln + 4lnx + -1lnx2 = 4

Reorder the terms:
-4 + 1ln + 4lnx + -1lnx2 = 4 + -4

Combine like terms: 4 + -4 = 0
-4 + 1ln + 4lnx + -1lnx2 = 0

The solution to this equation could not be determined.

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